(25p^2)-38p=0

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Solution for (25p^2)-38p=0 equation:



(25p^2)-38p=0
a = 25; b = -38; c = 0;
Δ = b2-4ac
Δ = -382-4·25·0
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38)-38}{2*25}=\frac{0}{50} =0 $
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38)+38}{2*25}=\frac{76}{50} =1+13/25 $

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